Graco Maxi-Flo System Manual de usuario Pagina 2

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Trabon
®
Maxi-Flo
®
System
L23110
Page 2
Inlet
5T
10T
15S
10S
End
.005 .010 .020 .030 .010 .005
124
Ratio
1 Cycle
62 1
Actual Cu. In.
Relative
Amounts
1
2
3
4
5
6
7
8
.080
Lubricant
Figure 4 The Basic Ratio
To obtain the basic ratios of a group of bearings, divide the lubricant
requirements of each bearing by the smallest oil requirements of the
group. (Refer to calculating lube requirements, Trabon Application
Engineering Lit. No. L20115.)
Example:
This illustration shows both the relative and actual quantity of oil
discharged during one complete cycle of the divider valve.
It can be seen in Figure 5 that the total oil discharged by the divider
valve during one cycle is .080 cubic inches. Conversely, if .080
cubic inches of oil is supplied to the inlet of this divider valve it will
complete one cycle.
(One cycle equals Ts x 2)
(Where Ts = total of intermediate section sizes)
MJ Divider Valve
Siz e
Volume (in
3
)
Per Outlet
5T .005
10T 5S .010
15T .015
10S .020
15S .030
Figure 3
T = Two Outlets S = One Outlet
Relative Size of A to B
A
B
3
2
A
B
3
2
1.5 to 1
=
=
Figure 5 Proportioning
Examples:
By multiplying the basic ration by the smallest intermediate section
capacity (5) the actual section size can be determined.
Crossporting joins two adjacent intermediate sections, thus
combining their capacities.
Example: 15 S & 15 S yields .060 cu.in./cycle
10 S & 10 S yields .040 cu.in./cycle
A wide range of ratios are available.
Example:
SYSTEM DESIGN
Proportioning
The proportioning of oil in a Maxi-Flo system depends on the
relative size of the pistons in a divider valve. Therefore, to size the
pistons correctly one need only know the relative size of the oil
requirements. This relative size is called "The Basic Ratio."
5T & 15S
0.030
0.005
= 1:6
10T & 15S
0.030
0.010
= 1:3
10T & 15T
0.015
0.010
= 1:1.5
15S Sections
0.060
0.005
= 1:12
Bearing
Unit of Oil Required in a
Given Time Period
Basic Ratio
A 2 1
B 3 1.5
C 4 2
A = 2/2 =1 B = 3/2 = 1.5 C = 4/2 = 2
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